SOLUTION: I just want to double check on the problem I am working on now,it is much appreciated if i could get help or a tutor to correct me. Keith and Michelle went out to dinner. The to

Algebra ->  Inequalities -> SOLUTION: I just want to double check on the problem I am working on now,it is much appreciated if i could get help or a tutor to correct me. Keith and Michelle went out to dinner. The to      Log On


   



Question 936553: I just want to double check on the problem I am working on now,it is much appreciated if i could get help or a tutor to correct me.
Keith and Michelle went out to dinner. The total cost of the meal,including the tip, came to $53.70. If the combined tip came to $9.60, and each friend spent an equal amount, what are the possible amounts each friend paid not including tip?
In my answer I put:
53.70 = 9.60x
-------- --------
9.60. 9.60
X= 6
I'm not sure this is correct but I would like help,please?

Found 2 solutions by josgarithmetic, MathLover1:
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
Cost + Tips = $53.70

Tips = $9.60

Just the foods cost, $53.70 minus $9.60.

Two friends, equal cost for food and the tips.

%2853.70-9.60%29%2F2=FoodCostPerFriend, which does not include the tips.




$22.05 per friend for the food.

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

given:
The total cost of the meal,including the tip, came to $53.70.
If the combined tip came to $9.60,
and each friend spent an equal amount: so, Keith spent $x and Michelle $x
then both spent $2x=53.70 including the tip
question is what are the possible amounts each friend paid not including tip?
so, first exclude the tip:
both spent $2x=53.70-9.60 => $2x=44.1 excluding the tip
now solve for x to find the possible amounts each friend paid :
$x=44.1%2F2
$x=22.05<= amount that each friend paid