SOLUTION: find three consecutive even integers such that four times the first decreased by the second is 12 more than the twice the third. solve algebraically
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Question 936533: find three consecutive even integers such that four times the first decreased by the second is 12 more than the twice the third. solve algebraically Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! z = y + 2
y = x + 2
4x - y = 2z + 12
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put the system of linear equations into standard form
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y - z = -2
x - y = -2
4x - y - 2z = 12
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copy and paste the above standard form linear equations in to this solver:
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solution:
x = 22
y = 24
z = 26
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now by elimination:
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y - z = -2
x - y = -2
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add the two above equations:
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x - z = -4
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-4(x - z = -4)
4x - y - 2z = 12
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add the two above equations:
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-y + 2z = 28
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-y + 2z = 28
y - z = -2
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add the two above equations:
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z = 26
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solution by elimination:
x = 22
y = 24
z = 26
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