SOLUTION: how do you find the inverse of a logarithm function my problem question is y=4log3(x)+1 the base or small number in the log function is 3 i know you have to substitute x for y

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: how do you find the inverse of a logarithm function my problem question is y=4log3(x)+1 the base or small number in the log function is 3 i know you have to substitute x for y       Log On


   

Question 936473: how do you find the inverse of a logarithm function
my problem question is y=4log3(x)+1
the base or small number in the log function is 3
i know you have to substitute x for y when you are doing the inverse and i got to the step x= 4log3(y)+1 but i am stuck on what to do after you substitute it.
Found 2 solutions by ankor@dixie-net.com, stanbon:
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
find the inverse of a logarithm function
my problem question is y=4log3(x)+1
Starting with what you have
4log%283%2C%28y%29%29+%2B+1+=+x
4log%283%2C%28y%29%29+=+x+-+1
log%283%2C%28y%5E4%29%29+=+x+-+1
Write the exponent equiv of logs
y%5E4+=+3%5E%28%28x-1%29%29
find the 4th root of both sides
y+=+%283%5E%28%28x-1%29%29%29%5E%281%2F4%29
y+=+3%5E%28%28x-1%29%2F4%29; exponent is %28%28x-1%29%2F4%29

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
find the inverse of a logarithm function
my problem question is y=4log3(x)+1
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Interchange x and y to get:
4log3(y)+1 = x
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Solve for "y"::
log3(y^4) = x-1
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y^4 = 3^(x-1)
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y = 3^[(x-1)/4]
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Cheers,
Stan H.
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