SOLUTION: FOR PROBLEMS 18 - 20 USE THESE MATRICES: A = [2 1 7 4 3 8 6 5 9] B = 0 2 3 Find A2,1 If C = AxB, the order of C is

Algebra ->  Matrices-and-determiminant -> SOLUTION: FOR PROBLEMS 18 - 20 USE THESE MATRICES: A = [2 1 7 4 3 8 6 5 9] B = 0 2 3 Find A2,1 If C = AxB, the order of C is      Log On


   



Question 93647: FOR PROBLEMS 18 - 20 USE THESE MATRICES:
A = [2 1 7
4 3 8
6 5 9]



B = 0
2
3
Find A2,1

If C = AxB, the order of C is:


If C=AxB, find C2,1.


Thank you in advance for your help - these are so tough for me

Answer by jayanthihemkos@yahoo.com(87) About Me  (Show Source):
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FOR PROBLEMS 18 - 20 USE THESE MATRICES:
A = [2 1 7
4 3 8
6 5 9]



B = 0
2
3
Find A2,1

ANS: 4 ( i.e the element in the second row first column)
If C = AxB, the order of C is:
Order of A = 3x3 matrix
Order of B = 3x1 matrix
Oder of C = AxB = 3x1 (row of A x column of B )

(3x 1)
If C=AxB, find C2,1.
C= AXB = [ 2x0+1x2+7x3
4x0+3x2+8x3
6x0+5x2+9x3]
= [0+2+21
0+6+24
0+10+27]
C= AXB
= [23
30
37]
C2,1 = 30 ( element of second row first column)


jayanthihemkos@yahoo.com