SOLUTION: Mrs. Merrill drives from Dallas to St.Louis. The length of the trip is 650 miles. She travels 50 miles per hour. Her husband leaves two hours later and travels at 62.5 miles per ho
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Question 936459: Mrs. Merrill drives from Dallas to St.Louis. The length of the trip is 650 miles. She travels 50 miles per hour. Her husband leaves two hours later and travels at 62.5 miles per hour. At what distance from Dallas will Mr.Merrill catch up with his wife?
A.500 Miles
B.600 Miles
C.625 Miles
D. Mrs.Merril arrives in St.Louis before her husband.
You can put this solution on YOUR website! Mrs. Merrill drives from Dallas to St.Louis.
The length of the trip is 650 miles.
She travels 50 miles per hour.
Her husband leaves two hours later and travels at 62.5 miles per hour.
At what distance from Dallas will Mr.Merrill catch up with his wife?
:
Let t = time required to catch the Mrs
then
(t+2) = the Mrs travel time
:
When this occurs, they will have traveled the same distance
Writ a distance equation; dist the speed/time
62.6t = 50(t+2)
62.5t = 50t + 100
62.5t - 50t = 100
12.5t = 100
t = 100/12.5
t = 8 hrs
Find the distance traveled in 8 hrs
62.5 * 8 = 500 mi
