SOLUTION: the sum of 3 consecutive whole numbers is 2013. what is the sum of all the digits of these numbers?

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Question 936400: the sum of 3 consecutive whole numbers is 2013. what is the sum of all the digits of these numbers?
Answer by srinivas.g(540) About Me  (Show Source):
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let x-1,x,x+1 be the three consecutive whole numbers
their sum =(x-1)+x+((x+1)
=x-1+x+x+1
=3x
but the sum is 2013
3x= 2013
divide with on both sides
+3x%2F3++=+2013%2F3
+x=+671
x=671
x-1 =671-1 =670
x+1 = 671+1 =672
so the three consecutive whole numbers are 670,671,672