SOLUTION: How can I prove this? [sin(x)-cos(x)+1] / [sin(x)+cos(x)-1] = [sin(x)+1] / cos(x)

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Question 936236: How can I prove this?
[sin(x)-cos(x)+1] / [sin(x)+cos(x)-1] = [sin(x)+1] / cos(x)
Answer by oscargut(2103) About Me  (Show Source):
You can put this solution on YOUR website!
[sin(x)-cos(x)+1] / [sin(x)+cos(x)-1] = [sin(x)+1] / cos(x)
[sin(x)-cos(x)+1]cos(x) = [sin(x)+1][sin(x)+cos(x)-1]
sin(x)cos(x)-cos(x)cos(x)+cos(x) = sin(x)sin(x)+sin(x)cos(x)-sin(x)+sin(x)+cos(x)-1
-cos(x)cos(x) = sin(x)sin(x)-1

0= sin(x)sin(x)+cos(x)cos(x)-1
And the last equation is true
If you need more help or details you can contact me at:
mthman@gmail.com
Thanks