SOLUTION: Find the domain and range of g(x) = {{{ sqrt((x+1))^2 }}}

Algebra ->  Functions -> SOLUTION: Find the domain and range of g(x) = {{{ sqrt((x+1))^2 }}}      Log On


   

Question 936103: Find the domain and range of
g(x) = +sqrt%28%28x%2B1%29%29%5E2+
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Because +sqrt%28%28x%2B1%29%5E2%29+=+abs%28x%2B1%29 (assuming x is any real number), this means that

Domain: Set of all real numbers

Range: Set of real numbers y such that y+%3E=+0

We can see this with a graph


------------------------------------------------------------------------------------------------------------------------

If you need more one-on-one help, email me at jim_thompson5910@hotmail.com. You can ask me a few more questions for free, but afterwards, I would charge you ($2 a problem to have steps shown or $1 a problem for answer only).

Alternatively, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Any amount is greatly appreciated as it helps me a lot. This donation is to support free tutoring. Thank you.

Jim
------------------------------------------------------------------------------------------------------------------------