SOLUTION: Solve the logarithmic equation: log2 4+log2 x=6 I got x=2, is this correct?

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Question 936092: Solve the logarithmic equation: log2 4+log2 x=6
I got x=2, is this correct?
Found 3 solutions by Alan3354, MathLover1, MathTherapy:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
No.
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sub 2 for x, see if it works.

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

log%282%2C+4%29%2Blog%282%2C+x%29=6

log%282%2C+4x%29=6...in base 10
log%284x%29%2Flog%282%29=6
log%284x%29=6log%282%29
log%284x%29=log%282%5E6%29 ...if log same, then
4x=2%5E6
4x=64
x=64%2F4
x=16

Answer by MathTherapy(10556) About Me  (Show Source):
You can put this solution on YOUR website!
Solve the logarithmic equation: log2 4+log2 x=6
I got x=2, is this correct?
log2 4 + log2 x = 6

log2 4x = 6

4x = 26

4x = 64

x+=+64%2F4, or highlight_green%2816%29

OR

log2 4 + log2 x = 6

log2 22 + log2 x = 6

2 + log2 x = 6

log2 x = 6 - 2

log2 x = 4

x = 24

highlight_green%28x+=++16%29

You can do the check!! 

You should be able to determine if you're correct, or incorrect, I'm sure!!

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