SOLUTION: A woman is paid $20 for each day she works and forfeits $5 for each day she is idle. At the end of 25 days she nets $450. How many days did she work?
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Question 936086: A woman is paid $20 for each day she works and forfeits $5 for each day she is idle. At the end of 25 days she nets $450. How many days did she work? Found 2 solutions by pricerk, Theo:Answer by pricerk(1) (Show Source):
You can put this solution on YOUR website! x+y=25 where x is the number of days worked and y is days missed
20x-5y=450 $20 per day worked , -5 per day lost when not working
y=25-5
using substitution
20x -5(25-x) =450
20x - 125 -5x =450
15x-125=450
15x=450+125=575
x=575/15 = 23
x=23
x+y=25 23+y=25 y=25-23=2
20x-5y=460-10=450
You can put this solution on YOUR website! let x equal the number of days she is working.
let y equal the number of days she is idle.
total number of days is 25.
x + y = 25
when she works, she makes 20 dollars.
when she is idle she loses 5 dollars.
she makes a total of 450 dollars.
20x - 5y = 450
you have 2 equations that need to be solved simultaneously.
they are:
x + y = 25
20x - 5y = 450
solve for y in the first equation of x + y = 25 to get:
y = 25 - x
replace y with 25 - x in the second equation of 20x - 5y = 450 to get:
20x - 5 * (25 - x) = 450
simplify to get:
20x - 125 + 5x = 450
combine like terms to get:
25x - 125 = 450
add 125 to both sides of the equation to get:
25x = 575
divide both sides of the equation by 25 to get:
x = 23
she worked 23 days and she was idle 2.
she made 23 * 20 = 460 and she lost 2 * 5 = 10 to net a total of 450 dollars.
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