SOLUTION: A man cycles to a friend's house at 12 mph and arrives 1 hour late.
Next day he travels at 16 mph and arrives 1 hour early.
What speed must he travel to arrive on time?
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-> SOLUTION: A man cycles to a friend's house at 12 mph and arrives 1 hour late.
Next day he travels at 16 mph and arrives 1 hour early.
What speed must he travel to arrive on time?
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Question 936042: A man cycles to a friend's house at 12 mph and arrives 1 hour late.
Next day he travels at 16 mph and arrives 1 hour early.
What speed must he travel to arrive on time? Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! x = correct travel time
y = distance to friend's house
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s = d/t
t = d/s
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late:
x + 1 = y/12
12x + 12 = y
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early:
x - 1 = y/16
16x - 16 = y
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put the system of linear equations into standard form
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12x - y = -12
16x - y = 16
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copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
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solution:
x = correct travel time = 7
y = distance to friend's house = 96
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answer:
s = d/t
s = 96/7
s = 13.7 mph
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