SOLUTION: Simplify the expression (8x^-3 y^6)^-1/3 (2x^-3 y^-1) so that the result is in terms of positive exponents, only. answers 1) 1/ x^2 y^2 2) 4/x^2 y^3 3) x^2 y^3 4) 1/ 4x^2 y

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Simplify the expression (8x^-3 y^6)^-1/3 (2x^-3 y^-1) so that the result is in terms of positive exponents, only. answers 1) 1/ x^2 y^2 2) 4/x^2 y^3 3) x^2 y^3 4) 1/ 4x^2 y      Log On


   



Question 935979: Simplify the expression (8x^-3 y^6)^-1/3 (2x^-3 y^-1) so that the result is in terms of positive exponents, only.
answers
1) 1/ x^2 y^2
2) 4/x^2 y^3
3) x^2 y^3
4) 1/ 4x^2 y^3

Found 3 solutions by stanbon, Alan3354, MathLover1:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Simplify the expression (8x^-3 y^6)^-1/3 (2x^-3 y^-1) so that the result is in terms of positive exponents, only.
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(2xy^2)^-1 * (2/x^3y)
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= 2/[2xy^2*x^3y)
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= 1/[x^4y^3]
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Cheers,
Stan H.
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answers
1) 1/ x^2 y^2
2) 4/x^2 y^3
3) x^2 y^3
4) 1/ 4x^2 y^3

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Simplify the expression (8x^-3 y^6)^-1/3 (2x^-3 y^-1) so that the result is in terms of positive exponents, only.
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(8x^-3 y^6)^-1/3 (2x^-3 y^-1)
Assuming -1/3 is an exponent:
= (2x^-3 y^-1)/(8x^-3 y^6)^(1/3)
= (2x^-3 y^-1)/(2x^-1 y^2)
= y^-1/(x^2y^2)
= 1/(x^2y^3)

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
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+1%2F%28y%5E3x%5E2%29 <= your answer
as I can see, option 3) has x%5E2%2Ay%5E3 and need to be +1%2F%28y%5E3x%5E2%29