Question 935907: Find an question in the form y=ax^2+bx+c for the parabola passing through the points. (-4,-123), (3,-102), (-1,-6)
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! y = axx + bx + c
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(-4,-123):
16a - 4b + c = -123
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(3,-102):
9a + 3b + c = -102
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(-1,-6):
a - b + c = -6
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16a - 4b + c = -123
9a + 3b + c = -102
a - b + c = -6
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put the system of linear equations into standard form
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substitute:
x for a
y for b
z for c
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16x - 4y + z = -123
9x + 3y + z = -102
x - y + z = -6
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copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
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solution:
x = -9
y = -6
z = -3
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substitute:
a for x
b for y
c for z
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solution:
a = -9
b = -6
c = -3
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answer:
y = axx + bx + c
y = -9xx - 6x - 3
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