SOLUTION: Sheila needs 30 mL of a 19.2% acid solution for a chemistry experiment. She has a 12% acid solution and an 84% acid solution. How many milliliters of the 12% solution does she need
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Question 935579: Sheila needs 30 mL of a 19.2% acid solution for a chemistry experiment. She has a 12% acid solution and an 84% acid solution. How many milliliters of the 12% solution does she need to make the mixture?
You can put this solution on YOUR website! Sheila needs 30 mL of a 19.2% acid solution for a chemistry experiment. She has a 12% acid solution and an 84% acid solution. How many milliliters of the 12% solution does she need to make the mixture?
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let x=amount of 12% solution needed
30-x=amount of 84% solution needed
..
12%x+84%(30-x)=19.2%*30
.12x+25.2-.84x=5.76
.72x=19.44
x=27
How many milliliters of the 12% solution does she need to make the mixture? 27
You can put this solution on YOUR website! x = mL of 84% acid solution
y = mL of 12% acid solution
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x + y = 30
0.84x + 0.12y = 0.192*30
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put the system of linear equations into standard form
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x + y = 30
0.84x + 0.12y = 5.76
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copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
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answer:
x = mL of 84% acid solution = 3
y = mL of 12% acid solution = 27
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