SOLUTION: hello Teachers:can you help with this log problem? 3log2x=4...that x is a exp above the log2.-this is what I did. I moved the 3above the x and the put it in exp.form.And I did this

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: hello Teachers:can you help with this log problem? 3log2x=4...that x is a exp above the log2.-this is what I did. I moved the 3above the x and the put it in exp.form.And I did this      Log On


   

Question 935531: hello Teachers:can you help with this log problem? 3log2x=4...that x is a exp above the log2.-this is what I did. I moved the 3above the x and the put it in exp.form.And I did this to change it to exp. form...2exp.4=x exp.3..is this right?tks for any help
Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
Your described given equation: 3%2Alog%28b%2C%282%5Ex%29%29=4, and you did not indicate the base.

3%2Ax%2Alog%28b%2C2%29=4

log%28b%2C2%29=4%2F%283x%29

highlight%28b%5E%284%2F%283x%29%29=2%29