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Question 935525: Find three consecutive numbers whose sum is 9 greater than twice the largest number.
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! z = y + 1
y = x + 1
x + y + z = 2z + 9
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put the system of linear equations into standard form
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y - z = -1
x - y = -1
x + y - z = 9
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solution:
x = 10
y = 11
z = 12
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