SOLUTION: T is older than G, and the difference of their ages is 40. If forty years ago T was half as old as G will be in forty years, what is the sum of their ages?

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Question 935158: T is older than G, and the difference of their ages is 40. If forty years ago T was half as old as G will be in forty years, what is the sum of their ages?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
T is older than G, and the difference of their ages is 40.
t = g + 40
:
If forty years ago T was half as old as G will be in forty years,
t - 40 = 1%2F2(g+40)
t - 40 = 1%2F2g + 20
t = 1%2F2g + 20 + 40
t = 1%2F2g + 60
replace t with (g+40)
g + 40 = 1%2F2g + 60
g - 1%2F2g + 60 - 40
1%2F2g = 20
multiply both sides by 2
g = 40 yrs
therefore, obviously:
t = 80 yrs
:
what is the sum of their ages? 120 yrs