Question 9351: Please help me with this problem, I just can't seem to come up with the right formula. I will apreciate help in comming up with the correct formula. Thank you!
Two joggers left their homes, which are 21 miles apart, at the same time. They agree to meet at a point somewhere in between in 1.5 hours. If the rate of one of the joggers is 2 miles per hour faster than the other, find the rate of each jogger.
Answer by longjonsilver(2297)   (Show Source):
You can put this solution on YOUR website! OK, joggerA speed = x
so that joggerB speed = x+2.
Note also, if joggerA runs a distance d, then B must have run 21-d, since they have met somewhere.
now speed = distance/time so
for A: x = d/1.5 --> d = 1.5x --> eqn1
for B: x+2 = (21-d)/1.5
--> 1.5x+3 = 21-d
so, 1.5x + 3 = 21-(1.5x)
1.5x + 3 = 21-1.5x
3x = 18
so x = 6.
So joggerA runs at 6mph and B runs at 8mph
jon.
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