SOLUTION: A certain amount is invested at 5 % per year, and Php 7000 less than this amount is invested at 6% per year.The investment yield Php 8820 yearly.How much was each investment ? EXPL

Algebra ->  Customizable Word Problem Solvers  -> Finance -> SOLUTION: A certain amount is invested at 5 % per year, and Php 7000 less than this amount is invested at 6% per year.The investment yield Php 8820 yearly.How much was each investment ? EXPL      Log On

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Question 934986: A certain amount is invested at 5 % per year, and Php 7000 less than this amount is invested at 6% per year.The investment yield Php 8820 yearly.How much was each investment ? EXPLAIN pls
Answer by vicgonzerx(31) About Me  (Show Source):
You can put this solution on YOUR website!
FROM INVESTMENT FORMULA I=Pa*ia + Pb*ib--------formula 1
LET Pa=amount invested by 5%=.05
Pb=amount invested by 6%=.06 w/c =Pa-7000(it means 7000 less than the amount of Pa "note less tha this amount")
from the fomula 1
I=the frofit or investment yield =8820php
so
8820=Pa(.05) + Pa-7000(.06)
Pa=84,000 php-------amount investet by 5%
Pb=Pa-7000
Pb=84000-7000
Pb=77,000 php amount invested by 6%
cheking 84,000(.05)+77000(.06)=8820