SOLUTION: A smuggler leaves a private airfield at 06:00 and flies on a course of
N40degreesE at 200 km/h.
The plane is detected by radar at the police airport, which
is located 150 km nor
Algebra ->
Trigonometry-basics
-> SOLUTION: A smuggler leaves a private airfield at 06:00 and flies on a course of
N40degreesE at 200 km/h.
The plane is detected by radar at the police airport, which
is located 150 km nor
Log On
Question 934939: A smuggler leaves a private airfield at 06:00 and flies on a course of
N40degreesE at 200 km/h.
The plane is detected by radar at the police airport, which
is located 150 km northwest of the airfield. At 06:30 the police airplane leaves its airport with the intention of intercepting the smuggler at 08:30. Determine the course the police airplane must travel, to the nearest unit.
Thanks Answer by vicgonzerx(31) (Show Source):
You can put this solution on YOUR website! LET A=SMUGGLER STARTING POINT @ 6:OO
B=SMUGGLER POINT @ 6:30
C= POLICE POINT WHEN DETECTING THE SMUGGLER @6:30
D= POINT WHERE THE SMUGGLER INTERCEPTED BY THE POLICE @ TIME 8:30
rEQUIRED IS THE COURSE OF THE POLICE DURING INTERCEPTION==?
@ 6:30 THE SMUGGLER TRAVELED THE DISTANCE OF AB @ RATE 200KPH TIME TRAVELED IS 0.5HR
AB=VT
AB=200*.5
AB=100KM
@ TIME 8:30 THE SMUGGLER TRAVELED AT DISTANCE BD @ THE RATE OF 200KPH
SO..BD=200(8.5-6.5)=400KM
SEE ATTACHED DIAGRAM FOR THE BASIS OF GETTING THIS COURSE
403.89N 18.46DEG E------------ THE ANSWER
