Question 934761: The length of a swimming pool is twice the width. The area of the pool is 5000 ft^2. find the length and width of the pool. Found 2 solutions by stanbon, TimothyLamb:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The length of a swimming pool is twice the width. The area of the pool is 5000 ft^2. find the length and width of the pool.
Width = w
Length = 2w
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Equation:
Area = length*width
5000 = 2w*w
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2w^2 = 5000
w^2 = 2500
w = 50 ft
2w = 2*50 = 100 ft
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Cheers,
Stan H.
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You can put this solution on YOUR website! L = 2w
Lw = 5000
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Lw = 5000
(2w)w = 5000
2ww - 5000 = 0
ww - 2500 = 0
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the above quadratic equation is in standard form, with a=1, b=0 and c=-2500
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to solve the quadratic equation, by using the quadratic formula, copy and paste this:
1 0 -2500
into this solver: https://sooeet.com/math/quadratic-equation-solver.php
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the quadratic has two real roots at:
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w = 50
w = -50
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the negative root doesn't fit the problem statement, so use the positive root:
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w = 50
L = 2w
L = 100
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answer:
w = 50 ft
L = 100 ft
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