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Question 93475: Using the following form to find the equation of the line with an x-intercept of (-5/6,0) and a y-intercept of (0,-7/3)
The intercept form of the equation of a line with intercepts at (a,0) and (0,b) is x/a+ y/b=1, a not equal to 0, b not equal to 0.
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Using the following form to find the equation of the line with an x-intercept of (-5/6,0) and a y-intercept of (0,-7/3)
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Using the slope/intercept form: y = mx + b
Using the y intercept 0,-7/3: then y = mx - (7/3)
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Using the x intercept -5/6, 0; find m:
(-5/6)m - (7/3) = 0
(-5/6m) = +(7/3)
m = (7/3)/(-5/6)
Which is:
m = (7/3)*(-6/5)
m = -42/15 = -14/5
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The equation: y =  x - 
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The intercept form of the equation of a line with intercepts at (a,0) and (0,b) is x/a+ y/b=1, a not equal to 0, b not equal to 0.
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Put in the y = mx + b form
x/a + y/b = 1
y/b = -x/a + 1; subtracted x/a from both sides
y = -bx/a + b; multiply both sides by b
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Hope this is what you mean here
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