SOLUTION: stan invested part of his 1000 at an annual rate of 6% and part of it at 9%. If his return of the two investments is $66 how much did he invest at each rate
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Question 934626: stan invested part of his 1000 at an annual rate of 6% and part of it at 9%. If his return of the two investments is $66 how much did he invest at each rate Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! x = amount invested at 6%
y = amount invested at 9%
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x + y = 1000
0.06x + 0.09y = 66
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put the system of linear equations into standard form
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x + y = 1000
0.06x + 0.09y = 66
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https://sooeet.com/math/system-of-linear-equations-solver.php
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solution:
x = amount invested at 6% = 800
y = amount invested at 9% = 200
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