SOLUTION: 2-5/x^2-x-6=x+3/x+2 identify and non permissible values

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Question 934620: 2-5/x^2-x-6=x+3/x+2 identify and non permissible values
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
2-5/x^2-x-6=x+3/x+2 identify ?? and non permissible values
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2- 5/[(x-3)(x+2)] = (x+3)/(x+2)
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Multiply thru by (x-3)(x+2) to get:
2(x^2-x-6) - 5 = (x-3)(x+3)
x^2-x-6 = 5
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x^2-x-11 = 0
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x = [1 +- sqrt(1-4*1*-1)]/2
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x = [1 +- sqrt(5)]/2
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Non-permissible values:: x = 3 and x = -2
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Cheers,
Stan H.
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