SOLUTION: Katrina walked from her house to the library. Then she walked 1/3 mile to her friend's house. When she left her friend's house she walked 2/5 miles home. How far did she walk from

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: Katrina walked from her house to the library. Then she walked 1/3 mile to her friend's house. When she left her friend's house she walked 2/5 miles home. How far did she walk from       Log On

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Question 934602: Katrina walked from her house to the library. Then she walked 1/3 mile to her friend's house. When she left her friend's house she walked 2/5 miles home. How far did she walk from her house to the library?

Answer by TimothyLamb(4379) About Me  (Show Source):
You can put this solution on YOUR website!
assume that katrina's house, the library, and her friend's house, are all in a straight line
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x = distance katrina's house to library
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x + 1/3 = 2/5
x = 2/5 - 1/3
x = 2*3/3*5 - 1*5/3*5
x = 6/15 - 5/15
x = 1/15 mile
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