SOLUTION: The length of two legs of an isosceles triangle are represented by 2×-5 and x+2. If the perimeter of the of the triangle is 24 find the length of the base.

Algebra ->  Triangles -> SOLUTION: The length of two legs of an isosceles triangle are represented by 2×-5 and x+2. If the perimeter of the of the triangle is 24 find the length of the base.       Log On


   

Question 934591: The length of two legs of an isosceles triangle are represented by 2×-5 and x+2. If the perimeter of the of the triangle is 24 find the length of the base.
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
The two legs of an isosceles triangle are the same length,
so if their length are represented by 2x-5 and x%2B2 , then
2x-5=x%2B2--->2x-x-5=2--->x-5=2--->x=2%2B5--->x=7 .
Then, the lengths of the legs are x%2B2=7%2B2=9 .
If the perimeter is 24 , then
base%2B9%2B9=24--->base%2B18=24--->base=24-18--->base=6 .
So, the length of the base is highlight%286%29 .