SOLUTION: solvex,y,z using matrix 3x-4y-z=-1 x=y-z=-2 2x-5y=2z=13

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Question 934468: solvex,y,z using matrix 3x-4y-z=-1
x=y-z=-2
2x-5y=2z=13

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
3x-4y-z=-1
x=y-z=-2.....I believe after x comes + sign
2x-5y=2z=13...after 5y comes + sign
3x-4y-z=-1
x%2By-z=-2
2x-5y%2B2z=13+


Initial Matrix
3 -4 -1 -1
1 1 -1 -2
2 -5 2 13

Taking matrix to echelon form:

multiplying row 1 by 0.3333}}}
adding -1 times row 1 to row 2
adding -1 times row 1 to row 3
multiplying row 2 by 0.4286
adding 2.3333 times row 2 to row 3
multiplying row 3 by 0.5

1 -1.3333 -0.3333 -0.3333
0 1 -0.2857 -0.7143
0 0 1 6

Taking matrix to reduced echelon form:
adding 1.3333 times row 2 to row 1
adding 0.7143 times row 3 to row 1
adding 0.2857 times row 3 to row 2
Reduced echelon form:
1 0 0 3
0 1 0 1
0 0 1 6
Result:
x+=+3
y=+1
z=+6