SOLUTION: what does the "" mean? What do I have to do on the graph paper? Using a scale of 2cm to 1 unit on the x and y axis, draw the graph of y = 2x+1 and x-3y= 2 for "-2<x<5"

Algebra ->  Linear-equations -> SOLUTION: what does the "" mean? What do I have to do on the graph paper? Using a scale of 2cm to 1 unit on the x and y axis, draw the graph of y = 2x+1 and x-3y= 2 for "-2<x<5"       Log On


   



Question 934439: what does the "" mean? What do I have to do on the graph paper?
Using a scale of 2cm to 1 unit on the x and y axis, draw the graph of y = 2x+1 and x-3y= 2 for "-2

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
It seems like the paper has to be
either graph paper somehow having squares measuring 2 cm,
or plain paper without lines.

One interpretation of the -2%3Cx%3C5 would be
that you have to show the graph of y=2x%2B1 from point (-2,-3) to point (5,11) ,
but that would make the graph 28 cm tall.

The -2%3Cx%3C5 must just mean that your scale on the x-axis should go from -2 to 5.
There is no instruction for the y-axis scale,
but -2 to 5 works well too (see below).
graph%28300%2C300%2C-2%2C5%2C-2%2C5%2C2x%2B1%2Cx%2F3-2%2F3%29
Since the scale is 2 cm to 1 unit,
the distance between marks on each axis would be 2 cm,
and the graph above would measure 14 cm by 14 cm.
To plot each line you would need 2 points, or a point and the slope.
y=2x%2B1 is an equation in slope-intercept form,
which makes it clear that the line has a slope of 2 ,
and a y-intercept of 1 , so (0,1) is one point,
and for every 1 unit increase in x, y increases by 2,
so with those increases, from (0,1) we get to (1,3),
and then to (2,5).
To graph y=2x%2B1 , you could plot points (0,1) and (2,5),
and draw the line that passes through them.
x-3y=2 is given in standard form,
so graphing it is not that easy.
You notice that for y=0 x=2 ,
so the line passes through (2,0).
The slope is 1%2F3 ,
so for every 3 units increase in x,
there is a 1 unit increase in y.
Using those increments, staring from (2,0), we get to (5,1),
so to graph x-3y=2you could points (2,0) and (5,1),
and draw the line that passes through them.
The lines seem to intersect at (-1,-1),
If you substitute x=-1 and x=-1 into the equations of both lines,
it makes the equations true.
That means that point (-1,-1) belongs to both lines,
so it is the intersection point,
and the solution to the system of equations
system%28y=2x%2B1%2Cx-3y=2%29 ,
which you have solved by graphing.
That was the point of the exercise.
Without the request to graph for -2%3Cx%3C5,
you could have made this graph:
graph%28300%2C300%2C-0.5%2C9.5%2C-0.5%2C9.5%2C2x%2B1%2Cx%2F3-2%2F3%29 ,
which does not show the intersection point.