Question 934397: A father is 24 years older than his son. In 7 years, the son's age will be 2/5 that of his father. What are their present ages? Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! x = father age
y = son age
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x = y + 24
y + 7 = (2/5)(x + 7)
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put the system of linear equations into standard form
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x - y = 24
y + 7 = (2/5)x + (14/5)
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x - y = 24
(2/5)x - y = 7 - (14/5)
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x - y = 24
0.4x - y = 4.2
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solution:
x = father age = 33
y = son age = 9
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