SOLUTION: Sue needed to return a bike she had borrowed from her friend. She can make the trip there and back in one hour by riding there and walking back. She can bike six times faster than
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Question 934390: Sue needed to return a bike she had borrowed from her friend. She can make the trip there and back in one hour by riding there and walking back. She can bike six times faster than she can walk. She can walk at the rate of two miles per hour. How long did she spend walking? Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! t = time walking
x = speed biking
y = speed walking = 2 mph
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x = 6y
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s = d/t
t = d/s
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time biking:
1 - t = d/x
1 - t = d/6y
t = 1 - d/6*2
t = 1 - d/12
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time walking:
t = d/y
t = d/2
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equate times:
1 - d/12 = d/2
1 = d/2 + d/12
1 = 6d/12 + d/12
1 = 7d/12
d = 12/7
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t = d/2
t = (12/7)/2
t = 0.857142857143 hours
t = (0.857142857143 hours) * (60 minutes/hour)
t = 51.43 minutes
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