SOLUTION: The base-path of a baseball diamond form a square. If it is 90 ft from home to first, how far does the catcher have to throw to catch someone stealing second base? plz helppppp

Algebra ->  Pythagorean-theorem -> SOLUTION: The base-path of a baseball diamond form a square. If it is 90 ft from home to first, how far does the catcher have to throw to catch someone stealing second base? plz helppppp      Log On


   

Question 934382: The base-path of a baseball diamond form a square. If it is 90 ft from home to first, how far does the catcher have to throw to catch someone stealing second base? plz helppppp
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
a^2 + b^2 = c^2 ... pythagorean theorem

90^2 + 90^2 = c^2

8100 + 8100 = c^2

2*8100 = c^2

c^2 = 2*8100

c = sqrt(2*8100)

c = sqrt(2)*sqrt(8100)

c = sqrt(2)*90

c = 90*sqrt(2)

The exact distance is 90sqrt%282%29 which approximates to 127.2792 feet.

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