SOLUTION: In the expression "6ab" - "a" being 7, and "b" being 8, how do you evaluate? I don't know whether to multiply "a" times "b" first, then multiply the product by 6, or do I multiply

Algebra ->  Expressions-with-variables -> SOLUTION: In the expression "6ab" - "a" being 7, and "b" being 8, how do you evaluate? I don't know whether to multiply "a" times "b" first, then multiply the product by 6, or do I multiply       Log On


   

Question 934378: In the expression "6ab" - "a" being 7, and "b" being 8, how do you evaluate? I don't know whether to multiply "a" times "b" first, then multiply the product by 6, or do I multiply each value by 6, such as 6x7 and 6x8 and add them together
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
6ab Start with the given expression


6%2A%287%29%2Ab Replace 'a' with 7 (since a+=+7)


6%2A%287%29%2A%288%29 Replace 'b' with 8 (since b+=+8)


336 Multiply


Therefore, 6ab+=+336 when a+=+7 and b+=+8
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