SOLUTION: the perimeter of a rectangle is 160ft. one fourth the length is the same as twice the width. find dimensions of the rectangle. round your answers to the nearest tenth or leave your

Algebra ->  Test -> SOLUTION: the perimeter of a rectangle is 160ft. one fourth the length is the same as twice the width. find dimensions of the rectangle. round your answers to the nearest tenth or leave your      Log On


   

Question 934364: the perimeter of a rectangle is 160ft. one fourth the length is the same as twice the width. find dimensions of the rectangle. round your answers to the nearest tenth or leave your answers as a fraction.
Answer by josgarithmetic(39625) About Me  (Show Source):
You can put this solution on YOUR website!
w and L, width and length;
L%2F4=2w, and 2w%2B2L=160.