SOLUTION: Which ordered pair is the vertex of f(x) = x2 – 10x + 16?

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Question 934253: Which ordered pair is the vertex of f(x) = x2 – 10x + 16?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+f%28x%29+=+x%5E2+-+10x+%2B+16+
When form is:
+f%28x%29+=+a%2Ax%5E2+%2B+b%2Ax+%2B+c+, then
then +x%5B+vertex%5D+=+-b+%2F+%282a%29+
+a+=+1+
+b+=+-10+
+c+=+16+
+-b%2F%282a%29+=+-%28-10%29+%2F+%28+2%2A1+%29+
+-b+%2F+%282a%29+=+10+%2F+2+
+-b+%2F+%282a%29+=+5+
Now find +y%5Bvertex%5D+
+y%5Bvertex%5D+=+1%2A5%5E2+-+10%2A5+%2B+16+
+y%5Bvertex%5D+=+25+-+50+%2B+16+
+y%5Bvertex%5D+=+-9+
---------------------
The vertex is at ( 5, -9 )
Here's the plot:
+graph%28+400%2C+400%2C+-10%2C+10%2C+-10%2C+10%2C+x%5E2+-+10x+%2B+16+%29+