SOLUTION: You invested $6000 between two accounts paying 5% and 9%, respectively. If the total interest earned for the year was $500, how much was invested at each rate
Algebra ->
Customizable Word Problem Solvers
-> Finance
-> SOLUTION: You invested $6000 between two accounts paying 5% and 9%, respectively. If the total interest earned for the year was $500, how much was invested at each rate
Log On
Question 934108: You invested $6000 between two accounts paying 5% and 9%, respectively. If the total interest earned for the year was $500, how much was invested at each rate Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! Part I 5.00% per annum ------------- Amount invested =x
Part II 9.00% per annum ------------ Amount invested = y
6000
Interest----- 500.00
Part I 5.00% per annum ---x
Part II 9.00% per annum ---y
Total investment
x + 1 y= 6000 -------------1
Interest on both investments
5.00% x + 9.00% y= 500
Multiply by 100
5 x + 9 y= 50000.00 --------2
Multiply (1) by -5
we get
-5 x -5 y= -30000.00
Add this to (2)
0 x 4 y= 20000
divide by 4
y = 5000
Part I 5.00% $ 1000
Part II 9.00% $ 5000