SOLUTION: The segment from a to b is subdivided by point c and d such that ac=twice cd and db= the sum of ac and cd find cd:ab

Algebra ->  Angles -> SOLUTION: The segment from a to b is subdivided by point c and d such that ac=twice cd and db= the sum of ac and cd find cd:ab       Log On


   



Question 934067: The segment from a to b is subdivided by point c and d such that ac=twice cd and db= the sum of ac and cd find cd:ab

Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
ab = ac + cd + db
ac = 2 * cd
db = ac + cd
find cd:ab which can also be shown as cd/ab.

if we let cd = x, then ac = 2*x.
so we have ac = 2*x and cd = x
we know that db = ac + cd, so db must be equal to x + 2*x = 3*x.
now we have ac = 2*x and cd = x and db = 3*x
we know that ab = ac + cd + db which means that ab = 2*x + x + 3*x which is equal to 6*x.
the ratio of cd to ab must therefore be equal to x / 6x which is equal to 1/6.