SOLUTION: If theta is an angle in Quadrant I and tan^2 theta - 4 = 0, what is the value of theta to the nearest degree?

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Question 934006: If theta is an angle in Quadrant I and tan^2 theta - 4 = 0, what is the value of theta to the nearest degree?
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

theta is an angle in Quadrant I

tan%5E2%28theta%29+-+4+=+0
tan%5E2%28theta%29+=4
tan%28theta%29+=sqrt%284%29
tan%28theta%29+=+2 or tan%28theta%29+=+-2
since theta is an angle in Quadrant I we will use only tan%28theta%29+=+2
if tan%28theta%29+=+2 => theta=63.43°