SOLUTION: what are the possible dimensions of a rectangle with an area of 264 square inches and a perimeter of 68 inches

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Question 933935: what are the possible dimensions of a rectangle with an area of 264 square inches and a perimeter of 68 inches
Answer by rothauserc(4718) About Me  (Show Source):
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l * w = 264 where l is length, w is width
2l + 2w = 68
l + w = 34
l = 34 - w
substitute for l in the first equation
(34-w) * w = 264
-w^2 +34w - 264 = 0
multiply both sides of = by -
w^2 -34w +264 = 0
factor the quadratic
(w-12)*(w-22) = 0
w can be 12 or 22
if w is 12 then l is 22
if w is 22 then l is 12