SOLUTION: Given 2x-6y=12 Transform the equation into slope intercept form and find the slope and y -intercept of the line and find the equation in slope intercept form of the line that is p

Algebra ->  Linear-equations -> SOLUTION: Given 2x-6y=12 Transform the equation into slope intercept form and find the slope and y -intercept of the line and find the equation in slope intercept form of the line that is p      Log On


   

Question 933669: Given 2x-6y=12
Transform the equation into slope intercept form and find the slope and y -intercept of the line and find the equation in slope intercept form of the line that is perpendicular to this line and passes through the point (-1,2). Show your work
Found 2 solutions by ewatrrr, stanbon:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
the standard slope-intercept form for an equation of a line is
y+=+highlight_green%28m%29x+%2B+highlight%28b%29 where m is the slope and b the y-intercept.
.........
2x-6y=12
y = (1/3)x - 2 , m = (1/3) (Green)
......
Line Perpendicular: m = -3/1 (negative reciprocal) %281%2F3%29%28-3%2F1%29+=+-1
***Using point-slope form, y+-+y%5B1%5D+=+highlight_green%28m%29%28x+-+x%5B1%5D%29P(-1,2)
y - 2 = -3(x+1)
y = -3x -1 (Blue)

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Given 2x-6y=12
Transform the equation into slope intercept form and find the slope and y -intercept of the line.
6y = 2x-12
y = (1/3)x - 2
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slope = (1/3) ; y-intercept = -2
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and find the equation in slope intercept form of the line that is perpendicular to this line and passes through the point (-1,2).
slope = -3
Form:: y = mx + b
Solve for "b"::
2 = -3*-1 + b
b = -1
---
Equation:
y = -3x -1
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Cheers,
Stan H.
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