Question 933554: 2secēθ+5tanθ=3
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! 2secēθ + 5tanθ = 3
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2(1+tan^2) + 5tan = 3
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2 + 2tan^2 + 5tan = 3
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2tan^2 + 5tan -1 = 0
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tan = [-5 +- sqrt(25-5*2*-1)]/2
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tan = [-5+-sqrt(35)]/2
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tan(t) = 0.4580 or tan(t) = -5.458 (extraneous)
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t = arctan(0.4580) = 24.61 degrees
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Cheers,
Stan H.
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