SOLUTION: John made a rectangular pen for his dog using 28 feet of fencing.
If the width of the pen is 2 feet more than one-half the length, what are the length and width of the pen?
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If the width of the pen is 2 feet more than one-half the length, what are the length and width of the pen?
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Question 93349: John made a rectangular pen for his dog using 28 feet of fencing.
If the width of the pen is 2 feet more than one-half the length, what are the length and width of the pen? Found 2 solutions by checkley75, praseenakos@yahoo.com:Answer by checkley75(3666) (Show Source):
You can put this solution on YOUR website! W=L/2+2
2W+2L=28
2(L/2+2)+2L=28
L+4+2L=28
3L=28-4
3L=24
L=24/3
L=8 ANSWER FOR THE LENGTH.
W=8/2+2
W=4+2
W=6 ANSWER FOR THE WIDTH
PROOF
2*8+2*6=28
16+12=28
28=28
You can put this solution on YOUR website! Question:
John made a rectangular pen for his dog using 28 feet of fencing.
If the width of the pen is 2 feet more than one-half the length, what are the length and width of the pen?
Answer:
Given data:
* Recangular Pen
* 28 feet fencing ==> perimeter of the rectangle is 28 feet.
* width of the pen is 2 feet more than one-half the length.
Let us assume that , length = x feet.
One half of the length =
2 feet more than one-half the length = + 2
Therefore, width = + 2
Perimeter of the rectangle is given by the formula,
(
