SOLUTION: Solve the equation in the real number system. {{{ 2x^3-x^2-6x+3=0 }}}

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Question 933445: Solve the equation in the real number system.
+2x%5E3-x%5E2-6x%2B3=0+
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
+2x%5E3-x%5E2-6x%2B3=0+...group
+%282x%5E3-x%5E2%29-%286x-3%29=0+...factor
+x%5E2%282x-1%29-3%282x-1%29=0+
+%28x%5E2-3%29%282x-1%29=0+
solutions:
if +x%5E2-3=0+=> +x%5E2=3+=> +x=sqrt%283%29=1.73+ or +x=-sqrt%283%29=-1.73+
if+2x-1=0+=>2x=1=>x=1%2F2=0.5

+graph%28600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+%28x%5E2-3%29%282x-1%29%29+