|
Question 933361: The sustainability club held a fundraiser where they sold 50 tickets to the Red Sox game, and they raised a total of $1590. If the bleacher seats were sold for $25 each and regular seats were sold for $42 each, how many of each type of tickets did the club sell?
I need help with how to approach this and also solve this.
Answer by LisaDrapeau(7)   (Show Source):
You can put this solution on YOUR website! First, break down what they are saying and write all statements as equations:
1. There are two types of seats: $25 ones and $50 dollar ones. Assign variables for these types of seats
X = $25 seats, Y = $42 seats
2. The amount of seats sold (number of tickets) is 50.
X + Y = 50
3. Total money raised is $1590.
25X + 42Y = 1590 ($25*number of X seats PLUS $42*number of Y seats = total amount of money made)
This is a system of equations. Since you have 2 unknowns you need two equations to solve them, and that is what we have:
X + Y = 50
25X + 42Y = 1590
Isolate any variable from one equation, and insert it into the other:
X = 50 - Y [isolating X in first equation]
25(50-Y) + 42Y = 1590 [inserting it into second equation]
1250 - 25Y + 42Y = 1590 [solving for Y]
17Y = 340
Y = 20
So 20 of the $42 seats were sold. Now put that answer into either equation to find how many $25 seats were sold (X seats).
X + 20 = 50
X = 30
To Check:
20+30 does equal 50 and:
25(30) + 20(42) = 1590 ???
750 + 840 = 1590 ???
1590 = 1590 YES
Hope that helps :)
|
|
|
| |
