SOLUTION: For each sequence, find a closed formula for the general term, a sub n. 1. 53,477,4293,38637,347733,... a sub n = 2. 2,5,10,17,26,...a sub n = 3. -2,-8,-18,-32,-50,...a sub n =

Algebra ->  Sequences-and-series -> SOLUTION: For each sequence, find a closed formula for the general term, a sub n. 1. 53,477,4293,38637,347733,... a sub n = 2. 2,5,10,17,26,...a sub n = 3. -2,-8,-18,-32,-50,...a sub n =       Log On


   



Question 933337: For each sequence, find a closed formula for the general term, a sub n.
1. 53,477,4293,38637,347733,... a sub n =
2. 2,5,10,17,26,...a sub n =
3. -2,-8,-18,-32,-50,...a sub n =
Help would truly be appreciated!

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
a sub n means the "nth" term of the sequence.
Example: 1,2,3,4,5,....,
the nth term is n. We say "a sub n = n"
Example 2: 1,4,9,16,25,...
We say "a sub n = n^2".


1. 53,477,4293,38637,347733,...
to get next term multiply previous one by 9
a sub n =a%5Bn%5D=53%2A9%5En(for all terms given)
if n=0,1,2...
check:
a%5B0%5D=53%2A9%5E0=53
a%5B1%5D=53%2A9%5E1=477
a%5B2%5D=53%2A9%5E2=4293
a%5B3%5D=53%2A9%5E3=38637
a%5B4%5D=53%2A9%5E4=347733
or
a%5Bn%5D+=+53+%2A9%5E%28n-1%29 if n=1,2...
check:
a%5B1%5D+=+53+%2A9%5E%281-1%29=53%2A9%5E0=53%2A1=53
:
:
I prefer this one because is better to have a%5B1%5D as first term


2. 2,5,10,17,26,...
pattern
2---- 5---- 10---- 17---- 26,..
-- 3---- 5---- 7-- 9...............first diff
---- 2---- 2---- 2................second diff.; all 2s, so degree is 2, half of it (or 1)will be coefficient of n%5E2
use
an%5E2+%2B+bn+%2B+c , set up system of three equations to find coefficients a,b, and c
For instance, I know that the first term (that is, the term when n = 1) is 2, so I'll plug in 1 for n and 2 for the value:
a%281%29%5E2+%2B+b%281%29+%2B+c+=+a+%2B+b+%2B+c+=+2
The second term (that is, the term when n+=+2) is 5, so:
a%282%29%5E2+%2B+b%282%29+%2B+c+=+4a+%2B+2b+%2B+c+=+5
The third term (that is, the term when n+=+3) is 10, so:
a%283%29%5E2+%2B+b%283%29+%2B+c+=+9a+%2B+3b+%2B+c+=+10

a+%2B+b+%2B+c+=+2.........1
4a+%2B+2b+%2B+c+=+5...........2
9a+%2B+3b+%2B+c+=+10...........3
___________________________
a+%2B+b+%2B+c+=+2.........1
a++=+2-+b+-c...plug in 2..........................a
4%282-+b+-c%29%2B+2b+%2B+c+=+5...........2
8-+4b+-4c%2B+2b+%2B+c+=+5
8-+2b+-3c=+5
8-+5-3c=+2b
3-3c=+2b
3%2F2-3c%2F2=+b ...........................b
9%282-+b+-c%29+%2B+3b+%2B+c+=+10...........3...plug in a
18-9+b+-9c%2B+3b+%2B+c+=+10
18-6+b+-8c++=+10......plug in b
18-6%283%2F2-3c%2F2%29-8c+=+10-18
-9%2B9c+-8c+=+-8
c++=+-8%2B9
c++=1
find a and b:
3%2F2-3c%2F2=+b+
3%2F2-3%2A1%2F2=+b+
highlight%28b=0+%29
a++=+2-+b+-c
a++=+2-+0+-1
highlight%28a=1%29

so, we have a+=+1, b+=+0, and c+=+1, and the formula is:
1n^2 + 0n + 1 = n%5E2+%2B+1


so, a sub n =n%5E2%2B1(for all terms given)
3. -2,-8,-18,-32,-50,...a sub n =


-2 ---- -8 ---- -18---- -32 ---- -50
----..-6----..-10----..-14---..-18
---- .. -4---- .. -4---- .. -4.........third difference, -> 3rd degree; constant is -4, so half of it (or -2)will be coefficient of n^2
a sub n = -2n%5E2+(for all terms given)