SOLUTION: How would I write the equation in exponential form LOG6,37= x

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Question 932848: How would I write the equation in exponential form
LOG6,37= x
Found 2 solutions by rothauserc, Alan3354:
Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
6^x = 37
note that the logarithm rule states
if y = log base b (x), then x = b^y

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
log%286%2C37%29+=+x --> 6%5Ex+=+37
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What you need to remember about logs, is that the LOG is the exponent.
IMO, it's an unfortunate choice of the name (logarithm, that is).
If the name was similar to exponent, such as exlog, expolog, or something like that, people would have fewer problems with them.