SOLUTION: Anita has k dollars, Luke has (k+2) dollars, and Evan has (k-5) dollars. If k+25, how much money do they have in all?

Algebra ->  Average -> SOLUTION: Anita has k dollars, Luke has (k+2) dollars, and Evan has (k-5) dollars. If k+25, how much money do they have in all?      Log On


   

Question 932790: Anita has k dollars, Luke has (k+2) dollars, and Evan has (k-5) dollars. If k+25, how much money do they have in all?
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

Anita has k dollars, Luke has %28k%2B2%29 dollars, and Evan has %28k-5%29 dollars.
If k%2B25, then
k%2B25=k%2B%28k%2B2%29%2B%28k-5%29...solve for k
k%2B25=k%2Bk%2B2%2Bk-5
k%2B25=3k-3
3%2B25=3k-k
28=2k
k=14
so,
Anita has 14 dollars
Luke has %28k%2B2%29=16 dollars, and
Evan has %28k-5%29=9 dollars

how much money do they have in all: 14%2B16%2B9=39