SOLUTION: Please help with the following:
(16b^-2)^-1/2 Solution: b/4
When I work this problem, I get 4b.
(16b^-2)^-1/2
= (16/b^2)^-1/2
= (16)^-1/2 / (b^2)^-1/2
= 1/4 / 1/b
= 4b
Algebra ->
Exponents-negative-and-fractional
-> SOLUTION: Please help with the following:
(16b^-2)^-1/2 Solution: b/4
When I work this problem, I get 4b.
(16b^-2)^-1/2
= (16/b^2)^-1/2
= (16)^-1/2 / (b^2)^-1/2
= 1/4 / 1/b
= 4b
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Question 932677: Please help with the following:
(16b^-2)^-1/2 Solution: b/4
When I work this problem, I get 4b.
(16b^-2)^-1/2
= (16/b^2)^-1/2
= (16)^-1/2 / (b^2)^-1/2
= 1/4 / 1/b
= 4b
Where am I going wrong? Thanks! Answer by ewatrrr(24785) (Show Source):
