SOLUTION: Please help me with this problem!What is the length of the major axis for the ellipse with equation {{{64x^2+25y^2=1600}}}?

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Question 932661: Please help me with this problem!What is the length of the major axis for the ellipse with equation 64x%5E2%2B25y%5E2=1600?
Found 2 solutions by ewatrrr, josgarithmetic:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
64x%5E2%2B25y%5E2=1600
x%5E2%2F25+%2B+y%5E2%2F64+=+1
x%5E2%2F5%5E2+%2B+y%5E2%2F8%5E2+=+1
major axis (along x = 0) = 2•8 = 16

Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
64x%5E2%2B25y%5E2=1600

%2864%2F1600%29x%5E2%2B%2825%2F1600%29y%5E2=1

x%5E2%2F25%2By%5E2%2F64=1

x%5E2%2F%285%5E2%29%2By%5E2%2F%288%5E2%29=1
The longer axis is along the y-axis, and the distance from center of the ellipse to the vertex along this major axis of the ellipse is 8. The length of the major axis is 2%2A8=highlight%2816%29.