SOLUTION: Please explain the method used to solve these: Solve triangle ABC. (If an answer does not exist, enter DNE. Round your answers to one decimal place.) b = 67, c = 38, &#8736

Algebra ->  Trigonometry-basics -> SOLUTION: Please explain the method used to solve these: Solve triangle ABC. (If an answer does not exist, enter DNE. Round your answers to one decimal place.) b = 67, c = 38, &#8736      Log On


   



Question 932635: Please explain the method used to solve these:
Solve triangle ABC. (If an answer does not exist, enter DNE. Round your answers to one decimal place.)
b = 67, c = 38, ∠A = 78°
∠B =____°
∠C =____°
a = ____
---------------------------------------
Solve triangle ABC. (If an answer does not exist, enter DNE. Round your answers to one decimal place.)
a = 17, b = 19, c = 25
∠A =____°
∠B =____°
∠C =____°

THANKS!

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Solve triangle ABC. (If an answer does not exist, enter DNE. Round your answers to one decimal place.)
b = 67, c = 38, A = 78°
B =____°
C =____°
a = ____
***
key:
angle: upper case letter
side opposite angle: lower case letter
..
Here are the steps to follow using Laws of Cosine and Sine:
a^2=b^2+c^2-2*b*c*cosA (solve for a)
sinA%2Fa=sinB%2Fb (solve for B)
C=180-(A+B)
---------------------------------------
Solve triangle ABC. (If an answer does not exist, enter DNE. Round your answers to one decimal place.)
a = 17, b = 19, c = 25
A =____°
B =____°
C =____°
***
Here are the steps to follow using Laws of Cosine and Sine:
a^2=b^2+c^2-2*b*c*cosA (solve for A)
sinA%2Fa=sinB%2Fb (solve for B)
sinA%2Fa=sinC%2Fc (solve for C)
..
To student: I will let you do the calculations to get the answers.