Question 932600: a cyclist is riding along at a constant velocity of 15 m/s. He then accelerates at a uniform rate of 0.50 m/s^2 over a distance of 64 m/s. How long did he accelerates for?
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! use one of the big 4 kinematic equations:
d = vi*t + (1/2)*a*t^2
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d = distance
vi = velocity initial
t = time
a = acceleration
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64 = 15t + (1/2)*0.50*tt
64 = 15t + (1/2)*(1/2)*tt
64 = 15t + (1/4)*tt
0.25tt + 15t - 64 = 0
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the above quadratic equation is in standard form, with a=0.25, b=15 and c=-64
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to solve the quadratic equation, by using the quadratic formula, copy and paste this:
0.25 15 -64
into this solver: https://sooeet.com/math/quadratic-equation-solver.php
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the quadratic has two real roots at:
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t = 4
t = -64
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the negative root doesn't fit the problem statement, so use the positive root:
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answer:
t = 4 seconds
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